(x+9)(4x^2-7x+3)=0

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Solution for (x+9)(4x^2-7x+3)=0 equation: 


Simplifying
(x + 9)(4x2 + -7x + 3) = 0

Reorder the terms:
(9 + x)(4x2 + -7x + 3) = 0

Reorder the terms:
(9 + x)(3 + -7x + 4x2) = 0

Multiply (9 + x) * (3 + -7x + 4x2)
(9(3 + -7x + 4x2) + x(3 + -7x + 4x2)) = 0
((3 * 9 + -7x * 9 + 4x2 * 9) + x(3 + -7x + 4x2)) = 0
((27 + -63x + 36x2) + x(3 + -7x + 4x2)) = 0
(27 + -63x + 36x2 + (3 * x + -7x * x + 4x2 * x)) = 0
(27 + -63x + 36x2 + (3x + -7x2 + 4x3)) = 0

Reorder the terms:
(27 + -63x + 3x + 36x2 + -7x2 + 4x3) = 0

Combine like terms: -63x + 3x = -60x
(27 + -60x + 36x2 + -7x2 + 4x3) = 0

Combine like terms: 36x2 + -7x2 = 29x2
(27 + -60x + 29x2 + 4x3) = 0

Solving
27 + -60x + 29x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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